Calculation method for installation of fan and wet curtain in chicken house
Chicken house fan and wet curtain installation calculation method, (the following is hypothetical) 1, chicken house area: 120m * 12m = 1440 square meters 2, chicken house area: 12m * (high) 2. 5 meters = 30 square meters 3, the maximum total body weight of chicken house: 1440 square meters * 12 birds / square meters * 2. 5 kg / only = 43200 kg 4, the maximum ventilation required: 43200 kg * 9 cubic meters per kilogram / hour = 388800 cubic meters 5, the number of fans required: 388800 cubic meters (except) assuming that each unit is 43000 cubic meters = 9 fans according to different models and manufacturers, according to the actual fan parameters, according to the size of the chicken coop needs to add 1-3 spare machines, the chicken coop needs to increase at least 3 sets Therefore, a total of 12 sets of 6 are required, and the maximum wind speed in the house: 388800 cubic meters (except) 3600 seconds (except) carrying area 30 square meters = 3 per second. 6 meters 7, wet curtain calculation: according to 15 cm thick through the wind speed requirements of 1 per second. 5-2 meters if it is 10 cm thick, press 1-1 per second through the wind speed. 5 meters calculation 8, the required wet curtain area: 388800 cubic meters (except) 3600 seconds (except) 1 per second. 5-2m = 54ft / 72m2 is generally taken as the median value of about 64 square meters of wet curtain area 9, above the calculation of negative pressure and chicken house wall air leakage coefficient, there is an increase in the backup machine is sufficient. 10. The ventilation rate per kilogram of body weight per hour is 7-9 cubic meters, with a large value in the south and a median value in the north. I hope the above calculation method can be useful for the design and installation of fan wet curtains for your reference.
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